Integrand size = 18, antiderivative size = 25 \[ \int \frac {1-x^2}{1+x^2+x^4} \, dx=-\frac {1}{2} \log \left (1-x+x^2\right )+\frac {1}{2} \log \left (1+x+x^2\right ) \]
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Time = 0.01 (sec) , antiderivative size = 25, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.111, Rules used = {1178, 642} \[ \int \frac {1-x^2}{1+x^2+x^4} \, dx=\frac {1}{2} \log \left (x^2+x+1\right )-\frac {1}{2} \log \left (x^2-x+1\right ) \]
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Rule 642
Rule 1178
Rubi steps \begin{align*} \text {integral}& = -\left (\frac {1}{2} \int \frac {1+2 x}{-1-x-x^2} \, dx\right )-\frac {1}{2} \int \frac {1-2 x}{-1+x-x^2} \, dx \\ & = -\frac {1}{2} \log \left (1-x+x^2\right )+\frac {1}{2} \log \left (1+x+x^2\right ) \\ \end{align*}
Time = 0.00 (sec) , antiderivative size = 25, normalized size of antiderivative = 1.00 \[ \int \frac {1-x^2}{1+x^2+x^4} \, dx=-\frac {1}{2} \log \left (1-x+x^2\right )+\frac {1}{2} \log \left (1+x+x^2\right ) \]
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Time = 0.03 (sec) , antiderivative size = 22, normalized size of antiderivative = 0.88
method | result | size |
default | \(-\frac {\ln \left (x^{2}-x +1\right )}{2}+\frac {\ln \left (x^{2}+x +1\right )}{2}\) | \(22\) |
norman | \(-\frac {\ln \left (x^{2}-x +1\right )}{2}+\frac {\ln \left (x^{2}+x +1\right )}{2}\) | \(22\) |
risch | \(-\frac {\ln \left (x^{2}-x +1\right )}{2}+\frac {\ln \left (x^{2}+x +1\right )}{2}\) | \(22\) |
parallelrisch | \(-\frac {\ln \left (x^{2}-x +1\right )}{2}+\frac {\ln \left (x^{2}+x +1\right )}{2}\) | \(22\) |
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Time = 0.25 (sec) , antiderivative size = 21, normalized size of antiderivative = 0.84 \[ \int \frac {1-x^2}{1+x^2+x^4} \, dx=\frac {1}{2} \, \log \left (x^{2} + x + 1\right ) - \frac {1}{2} \, \log \left (x^{2} - x + 1\right ) \]
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Time = 0.05 (sec) , antiderivative size = 19, normalized size of antiderivative = 0.76 \[ \int \frac {1-x^2}{1+x^2+x^4} \, dx=- \frac {\log {\left (x^{2} - x + 1 \right )}}{2} + \frac {\log {\left (x^{2} + x + 1 \right )}}{2} \]
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none
Time = 0.20 (sec) , antiderivative size = 21, normalized size of antiderivative = 0.84 \[ \int \frac {1-x^2}{1+x^2+x^4} \, dx=\frac {1}{2} \, \log \left (x^{2} + x + 1\right ) - \frac {1}{2} \, \log \left (x^{2} - x + 1\right ) \]
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none
Time = 0.27 (sec) , antiderivative size = 35, normalized size of antiderivative = 1.40 \[ \int \frac {1-x^2}{1+x^2+x^4} \, dx=\frac {1}{4} \, \log \left ({\left | x + \frac {1}{x + \frac {1}{x}} + \frac {1}{x} + 2 \right |}\right ) - \frac {1}{4} \, \log \left ({\left | x + \frac {1}{x + \frac {1}{x}} + \frac {1}{x} - 2 \right |}\right ) \]
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Time = 0.06 (sec) , antiderivative size = 10, normalized size of antiderivative = 0.40 \[ \int \frac {1-x^2}{1+x^2+x^4} \, dx=\mathrm {atanh}\left (\frac {x}{x^2+1}\right ) \]
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